What is the greatest number that on dividing 2400 and 1810 leave remainder 6 and 4 respectively?

- 40
- 36
- 24
- 42

Option 4 : 42

Since on dividing 2400, remainder 6 is left

So the required number must divide (2400 – 6) = 2394 exactly

Also, on dividing 1810, remainder 4 is left

So the required number must divide (1810 – 4) = 1806 exactly

So, the greatest number required number should be the HCF of 2394 and 1806

∴ HCF of 2394 and 1806 = 42

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